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by Arnavion
3365 days ago
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>while you would be left with 2/n - 1/(n^2) of BB For those like me who didn't immediately understand where this came from: P(atleast one of two boys satisfies the condition)
= 1 - P(neither of two boys satisfies the condition)
= 1 - [P(a boy doesn't satisfy the condition)]^2
= 1 - [1 - P(a boy satisfies the condition)]^2
= 1 - [1 - 1/n]^2
= 2/n - 1/n^2
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