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by TorKlingberg
3409 days ago
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Yes, a system with char >8 bits wouldn't have a uint8_t type at all. But, even when char and (u)int8_t are the same size, it may not be the same type. Compilers could go and apply strict aliasing for pointers to uint8_t. I'm at the limit of my C types knowledge here, so correct me if I'm just wrong. |
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