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by cnvogel
3407 days ago
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For typical Gamma radiation of about 1MeV photon energy or higher, you need about 1cm thickness of lead to reduce the radiation to about a third (by a factor of 1/ℯ). One order of magnitude of radiation hardness (reduce radiation to 1/10th) needs two centimeters of lead. That's getting heavy pretty fast. Radiation intensity inside your box depends on the thickness t: I(t) = I₀·exp(-tρμ) t: thickness, say 1 cm
ρ: density of the material, for Lead 11 g/cm³
μ: absorption coeffcient 0.1 cm²/g [see ref 1]
I₀: intensity outside of the box ...import numpy as np...
In [5]: np.exp(-0.1 * 11.34)
Out[5]: 0.32174370422037013
I(1cm) = 32,2%, I(2cm) = 10,4%[1] http://www.eichrom.com/PDF/gamma-ray-attenuation-white-paper... |
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