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by wyager 3499 days ago
Huh? No, anyone who writes it in Haskell would not use those lambda abstractions. You would just use "filter isValid (map Person names)".
1 comments

I'm assuming Person is a record constructor, is isValid here a field in that record or another function?
Haskell doesn't distinguish the two. If you define Person with named fields including isValid, you automatically get a function named isValid that returns that field, or you can write your own isValid function that examines the whole Person.