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by abaco 3564 days ago
Well that's because this is checking if a value may be a valid number. It's not safely converting the value to a number. That's done after a parseFloat()
1 comments

You guys make my point for me.

There's no way on earth we'd be arguing about such a ridiculously trivial thing for most other languages.

Nobody should have to look any of this up.

Yeah, we work around it ... but it drives me crazy. :)