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by wyager
3617 days ago
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> The injectivity assumption isn't unjustified Strongly disagree. (+2) 3 == (+1) 4 implies neither (+2) == (+1) nor 3 == 4. So Fst goes out the window. (even 5) == (even 7) does not imply 5 == 7. >type constructors are injective. But type functions aren't, and that's what we want. I agree that it's misleading to have type functions look like type constructors syntactically. |
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