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Pxl_Buzzard
3612 days ago
A solution: everyone is sequentially numbered. Evens rotate left one round, odds rotate right the next round. That way everyone has to move the same amount (assuming an even number of participants).
1 comments
peteretep
3612 days ago
If I understand you correctly, not everyone then sees everyone else, which is likely to breed customer dissatisfaction
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flukus
3612 days ago
That's a pre-existing problem.
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