|
|
|
|
|
|
by lohankin
3668 days ago
|
|
|
No, I meant something different.
Let's consider primes, say, between 1 and 1000000. a) Compute the number of cases when p is prime AND p+2 is prime; b) number of cases when p is prime AND p+4 is prime; c) number of cases when p is prime AND p+6 is prime.
My claim is that a is approx. equal to b, and c is approx. equal to 2a (which is the same as 2b). You can easily test it (which I did), and it's easy to see why. |
|
|