No. In C++, for instance, you can share data either by a const reference (or pointer), or by a non-const reference (or pointer). The latter allows mutation; the former does not.
Now, that means that the language is not forcing you to share without mutability, because you can leave off "const". That is, you have to be disciplined. But if you put "const" on the reference, the compiler won't permit you to modify the data through that reference.
Now, that means that the language is not forcing you to share without mutability, because you can leave off "const". That is, you have to be disciplined. But if you put "const" on the reference, the compiler won't permit you to modify the data through that reference.