[lmitchell]

Maybe a bit off-topic, but I just want to clarify - lambdas only include dynamic allocation if you convert them to an std::function, right? I was under the impression that 'auto f = []{...}' did no heap allocation, but converting to an std::function could, depending on the size of the closure.

[vvanders]

Yup your on the mark, it leads to some interesting scenarios where you can't easily refactor code without either introducing template hell or taking the hit for std::function.