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by MJSplot_author
3725 days ago
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Running their numbers: Assuming the usual sqrt(n+1) error on a count, as n is low. Combining the uncertainties from 83/66 [0] gives 1.258 +- 0.231 (1sd). It's only just likely that it is an actual improvement, but there is about a 30% chance that the orignal was better. [0] (((1+66^0.5)/66)^2+((1+83^0.5)/83)^2)^0.5x83.0/66 EDIT If we also include the errors on the total counts and use the fraction 83.0/66/6362x6392, then the error is: (((1+66^0.5)/66)^2+((1+83^0.5)/83)^2+((1+6362^0.5)/6362)^2+((1+6392^0.5)/6392)^2)^0.5x83.0/66/6362x6392 which shows an improvement of 1.264+-0.234. Stastically nout. |
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