[Rusky]

Are you saying C++ make it easy to write exception-safe code? Because Rust explicitly encodes exception safety into the type system with the RecoverySafe trait, you need to write unsafe code to bypass that, and the documentation on unsafe explicitly covers exception safety.

[Gankro]

Rust doesn't consider exception safety to be a matter worth 'unsafe's time. All code must simply be memory-safe in the face of unwinding. RecoverySafe is basically "it's hard to leak busted state out of a region of code that panicked". That is, mutable references aren't RecoverySafe, and mutexes and the like poison their contents if they witness a panic while locked.

But RecoverySafe is just preventing things like "your binary heap was only partially heapified" and not "your heap is now full of uninitialized memory". You can get poisoned values out of mutexes just fine, so everything needs to put itself in a memory-safe state if a panic occurs.

One can bypass RecoverySafe in safe code with the AssertRecoverySafe wrapper.

It does however turn out that safe code in Rust is generally quite exception-safe by default. This is because safe code can't do anything too dangerous, panics are generally only caught at thread or application boundaries (so data that witnesses a panic is usually well-isolated) and there's way less places that can unwind compared to "override everything" C++. But exception safety is indeed something unsafe code needs to fight for (see the aforementioned binary heap in std).

[quotemstr]

Rust's type system doesn't attempt to guard against resource leaks.

[Rusky]

It doesn't guarantee destructors will run, that's true, but that's for things like Rc cycles. Take a look at the RFC for std::panic::recover- it definitely takes exception safety into account: https://github.com/rust-lang/rfcs/blob/master/text/1236-stab...

Also take a look at things like the design of the Drain iterator- the stdlib is definitely (intended to be) exception safe.