| This is not my area of expertise, but to get things started, I went to a site[0] and looked up some formulas and specs, and came up with: outside circumference of wheel ~2200mm (700c wheel w/ tire)
30 mph == 0.5 mpm (Miles per minute).
0.5 mile == 804500mm
a 2200mm circumference will need to roll ~365.68 times to cover that distance. If that distance is covered in 1 minute, that means 365.68 rotations per minute. This: Ef = 1/2 I ω2 wants I and ω. I = m r squared. m == 700g (this isn't properly distributed here, but it's a start) r (at 2200mm circumference) == 350.14 0.7kg * ((350.14mm)(0.001m/mm))^2
== 0.7 * .122598019
== 0.085818613 kg/m2 1 rad/s = 9.55 r/min (rpm)
365rpm == 38.29 rad/s so if this is at all correct: Ef = 0.5 * 0.085818613 * 38.29^2
== 0.5 * 0.085818613 * 1466.1241
== 62.910368373 Joules 1J/s == 1watt. So with this fudgey math above (assuming it's even correct) we're working w/ ~60 watts(max, for an instance, then decreasing). I don't even know if that's enough to spin a bicycle around like was shown. I hope somebody that actually understands this field can chime in and fix my bad assumptions (which I think err to supporting this was strictly the spinning wheel (not a motor)) and what this means. I'll do practical tests later when I have my bike. [0] http://www.engineeringtoolbox.com/flywheel-energy-d_945.html |
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