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by random_coder
3751 days ago
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For 5), 89 modulo 77 is 12 so we just solve for the least m such that (m + 3) * (m + 4) (= mm + 7m + 12) is divisible by 77. Both 73 and 74 clearly satisfy the condition, but 18 + 3 = 21 divisible by 7 and 18 + 4 = 22 divisible by 11 is the least among the choices. |
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