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by klmr
3777 days ago
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No, unfortunately that is not the case. Lookup happens at execution of the byte code, because variables cannot be looked up at byte compilation. Consider the following case: x = 1
local({
assign(user_input, 2)
print(x)
}, envir = new.env(parent = environment()))
If `user_input` is “x”, the lookup of `x` in the local scope finds a different variable, in a different scope. Hence this lookup needs to take place every time this piece of code is executed.I’m not sure if Python suffers from similar problems. |
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