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by billconan 3805 days ago
Sorry, I don't get it.

the example you gave is like the following c++ code:

XXX *object = null;

if ((object = anotherpointer) != NULL)

{ ... }

The point is, ! is only useful, when it can detect null pointers during compiling time. but it doesn't.

the way ! is used, as suggested by your example, is also doable in C++, it is just a habit thing.

in c++, with good habit, you won't have problem. in Swift with bad habit, you will have the same problem.

then what good is !,

2 comments

No, you don't seem to be getting what I'm saying. I'm saying don't use !, and showing you how to avoid using it in a common pattern. Using 'if let' instead of ! does give you compile time verification of correctness.

! is there for the small number of cases where that's not possible. And it makes it much more obvious where you've got a potential problem, because the '!' is a literal code smell. You can't really do that with c++.

Ever since the guard statement was introduced I think you should never, ever use the ! as operator. It still has some sense when using as a type, for example for IBOutlets.