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by sorokod 3823 days ago
Given that

  p(A and B) = p(B and A)
  p(A and B ) = p(A) * p(B|A)
we have:

  p(A) * p(B|A) = p(B) * p(A|B)
  p(B|A) = p(B) * p(A|B) / p(A)