Hacker News new | ask | show | jobs
by grogenaut 3824 days ago
Thought about this for a bit. I'm betting it's used. The deal with brakes is the ratio of the friction applicable by the brake and the lever distance of the compared to the lever arm it's stopping. I'm watching a movie so I'm not going to do the math right now but I think the size of disc rotor you could get on say a mule's knee joint versus the lever arm length of say a lower leg might cause problems either with the size of the rotor.

My thinking is mountain bike discs are 120mm/4.8"-203mm/8" diameter compared to a 29" wheel.

These are meant to stop a 160lb person who is going down a hill. Well Slow to a stop not lock dead in place as the wheel would break free so it's not the full stopping power of a real.

Anyway my gut reaction is it might be difficult in this use case. I think a 8" rotor on a similar lever arm might have trouble fully locking down that joint and would be very large and flimsy (8" thin sheet of metal) for rugged use. Plausible though.

But hey I failed out of mechanical engineering into computer science for a reason so maybe I shouldn't be trusted :)

2 comments

Many robotics applications use ballscrew linear actuators. These contain a cage of ball bearings in a spiral around a ball screw, and they move a given distance for each revolution. You can apply a braking force to the ball screw, which will have a large mechanical advantage over trying to brake against the joint itself.
Very true. My cnc uses these. However I couldn't see getting it to walk or hop like these mules. You don't really get impulse with a ballscrew.
Think smaller. Most of the mechanism has to fit inside the dimensions of an arm or elbow.
I think you're missing that this is EXACTLY my point. I'm really doubting a disc that could fit inside an elbow would be able to stop the torque of a few hundred (900/4) lbs on it. Actually one inside the elbow would have a very minimal surface area on the disc in the first place.