i think the poster thinks that with the fat arrow definition, name becomes an implicitly called function wherever it is used. I wouldn't like that either.
but, I dont know if thats really the case though (I dont know ceylon). I think that fat arrow line would just become a no op instead, creating a lambda and throwing it away immediately ("name" being the param name in the lambda and nothing more).
but, I dont know if thats really the case though (I dont know ceylon). I think that fat arrow line would just become a no op instead, creating a lambda and throwing it away immediately ("name" being the param name in the lambda and nothing more).