Here's one way to reproduce the 40% number they get in the paper. Take a sequence of four flips. Consider five cases:
1. 0 heads. Probability of head following a head=0
2. 1 head. Probability of head following a head=0
3. 2 heads. Probability of head following a head = 1/3
4. 3 heads. Probability of head following a head = 2/3
5. 4 heads. Probability of head following a head = 1
Now if those five cases were equally likely, then what would be the expected number of heads following a head?
Answer: (0 + 0 + 1/3 + 2/3 + 1)/5 = 0.4
Is this what they assume gamblers are using for 'empirical probability'? I can't tell.
Here's one way to reproduce the 40% number they get in the paper. Take a sequence of four flips. Consider five cases:
1. 0 heads. Probability of head following a head=0
2. 1 head. Probability of head following a head=0
3. 2 heads. Probability of head following a head = 1/3
4. 3 heads. Probability of head following a head = 2/3
5. 4 heads. Probability of head following a head = 1
Now if those five cases were equally likely, then what would be the expected number of heads following a head?
Answer: (0 + 0 + 1/3 + 2/3 + 1)/5 = 0.4
Is this what they assume gamblers are using for 'empirical probability'? I can't tell.