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by codingbinary
3973 days ago
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That depends on your clustering algorithms. If it is for example based on shared-neighbor information, then you end up with the same clusters as you did before scaling. And in your example, I get: (A, B) < (B, C) < (A, C) before
and (A, B) < (B, C) < (A, C) after scaling. So the order is preserved. It really depends on your clustering algorithm. DBSCAN for example could end up with a different result due to its epsilon-range parameter. |
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