1
x + 1
x² + 2x + 1
x³ + 3x² + 3x + 1
...
You can think of Pascal's triangle as repeated multiplication by (x + 1).
(i.e. (x+1) = 1x^1 + 1x^0 => 1:1)
it makes sense, haven't thought about it..
1
x + 1
x² + 2x + 1
x³ + 3x² + 3x + 1
...
You can think of Pascal's triangle as repeated multiplication by (x + 1).