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The antiderivative of 1/x is ln(x), not ln |x (blog.danielh.cc)
2 points by max__dev 259 days ago
1 comments
NoahZuniga 258 days ago
Sir what you wrote down is equivalent to integral 1/x = ln|x| if x > 0 else ln|x| + pi*i
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gus_massa 258 days ago
1/x = ln|x| + C if x > 0

ln|x| + pi*i + C or ln|x| - pi*i + C or is x < 0 (Protip: Choose C=-+pi*i)

In reals ln|x| is fine.

In complex, it's a mess https://en.wikipedia.org/wiki/Complex_logarithm

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